A lever consists of a bar which pivots at a fixed point known as the fulcrum. In the example shown the fulcrum is at the center of the lever. This lever provides no mechanical advantage and the force needed to lift the weight is equal to the weight itself.

However, if you want to lift a weight that is heavier than the force applied you can move the fulcrum closer to the weight to be lifted. This affects the force required in the following way:

w x d1 = f x d2

Where: | w = weight |

d1 = distance from fulcrum to weight | |

f = force needed | |

d2 = distance from fulcrum to point where force is applied |

In this example the fulcrum has been moved towards the weight so that the weight is 1 meter from the fulcrum. This means that the force can now be applied 2 meters from the fulcrum.

If you needed to calculate the force needed to lift the weight then you can rearrange the formula.

**w x d1 = f x d2 ** can be rearranged
to **f = (w x d1)/d2**

**f = (10 x 1)/2 (10/2** is the same as 5/1, the force required
is 5 Kg)

**Example Questions**

1. How much force is required to lift the weight?

A) 40lbs |
B) 50lbs |
C) 60lbs |
D)70lbs |

**Answer**

1. C - 60lbs is needed to lift the weight. It can be calculated
like this:

f = (w x d1)/d2

f = (80 x 9)/12

f = (720)/12

f = 60 lbs

In practice, levers are used to reduce the force needed to move
an object, in other words to make the task easier. However, in
mechanical aptitude questions it is possible that you will see
questions where the fulcrum has been placed closer to the force
then the weight. This will mean that a force greater than the
weight will be required to lift it.

You may see more complex questions involving levers, where there
is more than one weight for example. In this case you need to work
out the force required to lift each weight independently and then
add them together to get the total force required.

2. How much force is required to lift the weights?

A) 25lbs |
B) 35lbs |
C) 40lbs |
D)45lbs |

**Answer**

2. B - 35lbs is needed to lift the weight. It can be calculated
like this:

f = (w1 x d1) + (w1a x d1a)/d2

f = (20 x 10) + (30 x 5)/10

f = (200 + 150)/10

f = 35 lbs

You may also be interested in: **Mechanical Aptitude Tests, Levers, Pulleys, Gears, Springs, Electricity, Tools **and** Shop Arithmetic. **